8 Problems for Michaelmas

8.3 Problems for section 3

For these problems, unless otherwise stated, G is a finite group and H is a subgroup of G.

Problem 34.

Let ρ be an irreducible representation of G. Show that ρ is isomorphic to a subrepresentation of a representation induced from an irreducible representation of H.

Solution

Problem 35.

Let χ be an irreducible character of H and let

IndHGχ=d1χ1++drχr

be decomposition of its induction into irreducible characters of G, with χi pairwise distinct and di0.

Show that

i=1rdi2[G:H].

Solution

Problem 36.

Let H be a subgroup of G. Show that:

  1. 1.

    If W1,W2 are representations of H, then

    IndHG(W1W2)IndHGW1IndHGW2.
  2. 2.

    If KG is a subgroup containing H, and W is a representation of H, then

    IndHGWIndKG(IndHKW).
  3. 3.

    If V is a representation of G, then

    IndHGResHGVVIndHG𝟙.

Note that all of these may be proved either from the definition (using the ’induction recognition’ corollary) or using characters and Frobenius reciprocity.

Solution

Problem 37.

Let HG be groups and let χ be a character of H. Let χ˙(g)=χ(g) if gH and 0 otherwise.

  1. 1.

    Show that the formula for the induced character may be rewritten

    (IndHGχ)(g)=1|H|xGχ˙(x-1gx).
  2. 2.

    If g1H,,grH are the left cosets of H in G, show that

    (IndHGχ)(g)=i=1rχ˙(gi-1ggi).

Solution

Problem 38.

For each irreducible representation of S4, decompose its induction to S5 (where S4 is regarded as the subgroup of elements of S5 that fix 5{1,,5}.)

Solution

Problem 39.

Let χ be the irreducible degree 3 character of H=A5 such that

χ((12345))=1+52.

Let G=A6, with H as the subgroup fixing 6. Compute the character

IndHG(χ).

Solution

Problem 40.

Let H=(12p)Sp=G, for p a prime, and χ be a nontrivial character of H.

  1. 1.

    Find

    IndHGχ.
  2. 2.

    By considering IndHGχ,IndHGχ, show that

    (p-1)!-1modp.

You may use that, if ζ is a nontrivial nth root of unity, then

1+ζ+ζ2++ζn-1=0.

Solution

Problem 41.

Let

G=a,x:a7=x3=e,xax-1=a2.

You may assume that G has 21 elements given by

{aixj:i=0,1,,6,j=0,1,2}.
  1. 1.

    Show that H=a is a normal subgroup of G.

  2. 2.

    By considering representations lifted from G/H and induced from H, find the character table of G.

Solution

Problem 42.

Fill in the missing proofs from section 3.6. (This is more of a mega-problem!)

Problems on Mackey theory

The remaining problems in this section concern Mackey theory, which we did not have time to cover and which is therefore not examinable. I leave them here in case you are interested.

Problem 43.

Suppose that G acts transitively on a set X, and that HG is the stabiliser of an element x0X.

Find a bijection between H\G/H and the orbits of G on the product X×X (with the action g(x,y)=(gx,gy)).

Solution

Problem 44.

For the following pairs of groups HG, find a set of double coset representatives for H in G.

  1. 1.

    H={e,s}G=D5

  2. 2.

    H={e,(123),(132)}G=S4

  3. 3.

    HS3×S2S5 the subgroup of elements σ such that σ preserves the subsets {1,2,3} and {4,5}.

Solution

Problem 45.

Prove Lemma 3.19: if H and K are subgroups of G and sG, then

HsK=h1sKhrsK

where h1,,hr are left coset representatives for

Hs=HsKs-1

in H.

Solution

Problem 46.

Suppose that H,K are subgroups of G and that their orders are coprime. Suppose that ρ is a representation of H and that σ is a representation of K. Show that

dimHomG(IndHGρ,IndKGσ)=dim(ρ)dim(σ)|G||H||K|.

Solution

Problem 47.

Suppose that HG is a subgroup of index two, that ϵ:G× is the nontrivial character with kernel H, and that sG is not in H.

Show that, if σ is an representation of G, then ResHGσ is irreducible if and only if σ≇ϵσ. Moreover, show that if σϵσ, then

ResHGσρρs

for ρ an irreducible representation of H with ρ≇ρs.

Solution

Problem 48.

Suppose that χ is an irreducible character of Sn whose degree χ(e) is odd. Show that there exists an odd permutation gSn such that χ(g)0.

Hint: use the previous problem.

Solution