7 SL3

7.7 Weyl symmetry — not examinable

Let s1, s2, and s3 be, respectively, reflections in the lines through L1, L2, and L3. Then any two of these (say s1 and s3) generate the Weyl group W, which is the group of symmetries of the triangle with vertices L1,L2,L3. So we have WD3S3. Note that W acts on the plane in a way that preserves the weight lattice. See Figure 10.

Simple reflections
Figure 10: Simple reflections
Theorem 7.25.

Let (ρ,V) be a finite-dimensional representation of 𝔰𝔩3,. Then the weights of V are symmetric with respect to the action of the Weyl group.

Proof.

We will prove they are symmetric with respect to s3 by using the inclusion

ι=ι12:𝔰𝔩2,𝔰𝔩3,

that puts a 2×2 matrix in the top left corner of a 3×3 matrix. We consider the restriction of V to 𝔰𝔩2,.

Note that if vV is a weight vector with weight aL1-bL3, then

ρ(ι(H))v=ρ((1-10))v=av.

Thus v is an 𝔰𝔩2,-weight vector with weight a. Note that ι(X)=E12, so an 𝔰𝔩2,-weight vector in V is an 𝔰𝔩2,-highest weight vector if it is killed by E12. Note also that ι(Y)=E21.

The kernel of E12 on V is preserved by (check it!) and so has a basis made up of 𝔰𝔩3,-weight vectors v1,,vr. These are then a maximal set of linearly independent highest weight vectors for 𝔰𝔩2, and in particular, if Vi is the 𝔰𝔩2,-representation generated by vi then, as an 𝔰𝔩2,-representation,

V=i=1rVi.

Fix i; it suffices to show that Vi has a basis of 𝔰𝔩3,-weight vectors whose weights are preserved by s3. Let vi have weight aL1-bL3. It follows from the 𝔰𝔩2,-theory that a0 and — remembering that ι(Y)=E21 — that Vi has a basis

v,E21v,,E21av.

By the FWC (Lemma 7.18) we see that these are weight vectors with weights

aL1-bL3,(a-1)L1+L2-bL3,,L1+(a-1)L2-bL3,aL2-bL3

which are symmetrical under s3 (this reflection swaps L1 and L2), as required. This argument is illustrated in Figure 11

Proof of Weyl symmetry
Figure 11: Proof of Weyl symmetry

Invariance with respect to the other reflections is proved similarly using the other inclusions ιij of 𝔰𝔩2, in 𝔰𝔩3,. ∎

Corollary 7.26.

Every highest weight is of the form aL1-bL3 for a,b0 integers. The region

{aL1-bL3:a,b0}

is called the dominant Weyl chamber and weights inside it (including the boundary) are dominant weights.

Proof.

Indeed, in the course of the proof of Theorem 7.25 we showed that if aL1-bL3 was a highest weight, then a0. A similar argument shows that b0. ∎

Dominant Weyl chamber
Figure 12: Dominant Weyl chamber
Exercise 7.27.

We can give another proof of Weyl symmetry using the Lie group SL3(). Let (ρ,V) is a representation of 𝔰𝔩3,. As SL3() is simply-connected ρ exponentiates to a representation, ρ~, of SL3(). Let

σ3=(010-100001)SL3().

Show that, for every weight α, ρ~(σ3) is an isomorphism

VαVs3α.

Give another proof of Theorem 7.25.