2.9. Lecture 9

2.9.1. Standard constructions for representations

We give a list of various constructions with representations of Lie groups, and the analogous constructions for their derivatives.

Definition 2.9.1.

The standard representation of a linear Lie group GGLn()G\subseteq\operatorname{GL}_{n}(\mathbb{C}) comes from its action on n\mathbb{C}^{n} so for 𝐯n{\bf v}\in\mathbb{C}^{n}

ρ(g)𝐯\displaystyle\rho(g){\bf v} =g𝐯\displaystyle=g{\bf v}
Dρ(X)𝐯\displaystyle D\rho(X){\bf v} =X𝐯.\displaystyle=X{\bf v}.
Definition 2.9.2.

The direct sum of representations (ρ1,V1)(\rho_{1},V_{1}), (ρ2,V2)(\rho_{2},V_{2}) of GG is (ρ1ρ2,V1V2)(\rho_{1}\oplus\rho_{2},V_{1}\oplus V_{2}) with derivative

D(ρ1ρ2)=Dρ1Dρ2.D(\rho_{1}\oplus\rho_{2})=D\rho_{1}\oplus D\rho_{2}.
Definition 2.9.3.

The determinant representation of GGLn()G\subseteq\operatorname{GL}_{n}(\mathbb{C}) is det:G\det:G\to\mathbb{C}^{*} which sends gg to det(g)\det(g). We have

Ddet(X)=tr(X),D\det(X)=\operatorname{tr}(X),

which follows from detexp(tX)=ettr(X)\det\exp(tX)=e^{t\operatorname{tr}(X)}.

Definition 2.9.4.

If (ρ,V)(\rho,V) is a representation of GG, the dual representation (ρ,V)(\rho^{*},V^{*}) of (ρ,V)(\rho,V) is defined by

(ρ(g)(λ))(𝐯)=λ(ρ(g1)(𝐯)),\left(\rho^{*}(g)(\lambda)\right)({\bf v})=\lambda\left(\rho(g^{-1})({\bf v})% \right),

for λV\lambda\in V^{*} a linear functional on VV and gGg\in G. It has derivative

Dρ(X)(λ)(𝐯)=λ(Dρ(X)𝐯).D\rho^{*}(X)(\lambda)({\bf v})=-\lambda(D\rho(X){\bf v}).

Given a basis of VV, then the matrix of ρ\rho^{*} with respect to the dual basis is

ρ(g)=ρ(g)T,\rho^{*}(g)=\rho(g)^{-T},

which differentiates to

(Dρ)(X)=Dρ(X)T.(D\rho^{*})(X)=-D\rho(X)^{T}.

We can take tensor/symmetric/alternating products of more than one factor.

Definition 2.9.5.

Suppose (ρi,Vi)(\rho_{i},V_{i}) are representations of GG. We form the tensor product

V1V2Vl.V_{1}\otimes V_{2}\otimes\ldots\otimes V_{l}.

It is generated by symbols 𝐯1𝐯l{\bf v}_{1}\otimes\ldots\otimes{\bf v}_{l} subject to the multilinear relations, i.e.

𝐯1(λ𝐯i+μ𝐯i)𝐯l=λ(𝐯1𝐯i𝐯l)+μ(𝐯1𝐯i𝐯l),{\bf v}_{1}\otimes\ldots\otimes(\lambda{\bf v}_{i}+\mu{\bf v}_{i}^{\prime})% \otimes\ldots\otimes{\bf v}_{l}=\lambda({\bf v}_{1}\otimes\ldots\otimes{\bf v}% _{i}\otimes\ldots\otimes{\bf v}_{l})+\mu({\bf v}_{1}\otimes\ldots\otimes{\bf v% }_{i}^{\prime}\otimes\ldots\otimes{\bf v}_{l}),

for each ViV_{i}. One has

dim(V1V2Vl)=i=1ldimVi.\dim\left(V_{1}\otimes V_{2}\otimes\ldots\otimes V_{l}\right)=\prod_{i=1}^{l}% \dim V_{i}.

The action of GG is

(ρ1ρl)(g)(𝐯1𝐯l)=ρ1(g)𝐯1ρl(g)𝐯l.(\rho_{1}\otimes\ldots\otimes\rho_{l})(g)({\bf v}_{1}\otimes\ldots\otimes{\bf v% }_{l})=\rho_{1}(g){\bf v}_{1}\otimes\ldots\otimes\rho_{l}(g){\bf v}_{l}.

for gGg\in G, 𝐯iVi{\bf v}_{i}\in V_{i}. We also write

Vl=VV.V^{\otimes l}=V\otimes\ldots\otimes V.
Lemma 2.9.6.

Suppose (ρ1ρn,V1Vn)(\rho_{1}\oplus\ldots\oplus\rho_{n},V_{1}\oplus\ldots\oplus V_{n}) is a tensor product of representations of GG. Then the derivative of this representation is given by

D(ρ1ρl)(X)=\displaystyle D(\rho_{1}\otimes\ldots\otimes\rho_{l})(X)= Dρ1(X)IdV2IdVl\displaystyle D\rho_{1}(X)\otimes\mathrm{Id}_{V_{2}}\otimes\ldots\otimes% \mathrm{Id}_{V_{l}}
+IdV1Dρ2(X)IdVl\displaystyle+\mathrm{Id}_{V_{1}}\otimes D\rho_{2}(X)\ldots\otimes\mathrm{Id}_% {V_{l}}
+\displaystyle+\ldots
+IdV1IdV2Dρl,\displaystyle+\mathrm{Id}_{V_{1}}\otimes\mathrm{Id}_{V_{2}}\ldots\otimes D\rho% _{l},

for all X𝔤X\in\mathfrak{g}.

Proof.

Suppose (π,V)(\pi,V), (ρ,W)(\rho,W) are representations of GG. Let X𝔤X\in\mathfrak{g}, 𝐯V{\bf v}\in V, 𝐰W{\bf w}\in W,then

D(πρ)(X)(𝐯𝐰)\displaystyle D(\pi\otimes\rho)(X)({\bf v}\otimes{\bf w}) =ddtπ(exp(tX))𝐯ρ(exp(tX))𝐰|t=0.\displaystyle=\left.\frac{d}{dt}\pi(\exp(tX)){\bf v}\otimes\rho(\exp(tX)){\bf w% }\right|_{t=0}.
=ddt(𝐯+tπ(X)𝐯+O(t2))(𝐰+tρ(X)𝐰+O(t2))|t=0\displaystyle=\left.\frac{d}{dt}({\bf v}+t\pi(X){\bf v}+O(t^{2}))\otimes({\bf w% }+t\rho(X){\bf w}+O(t^{2}))\right|_{t=0}
=ddt𝐯𝐰+t(π(X)𝐯𝐰+𝐯ρ(X)𝐰)+O(t2)|t=0\displaystyle=\left.\frac{d}{dt}{\bf v}\otimes{\bf w}+t(\pi(X){\bf v}\otimes{% \bf w}+{\bf v}\otimes\rho(X){\bf w})+O(t^{2})\right|_{t=0}
=π(X)𝐯𝐰+𝐯ρ(X)𝐰\displaystyle=\pi(X){\bf v}\otimes{\bf w}+{\bf v}\otimes\rho(X){\bf w}

as required. We can then apply an inductive argument to show this hold for all tensor products. ∎

Definition 2.9.7.

Let (ρ,V)(\rho,V) be a representation of GG. The llth symmetric product is the space Syml(V)\operatorname{Sym}^{l}(V) generated by symbols 𝐯1𝐯l{\bf v}_{1}\ldots{\bf v}_{l} with linearity in each of the 𝐯i{\bf v}_{i}s and any permutation of the vectors giving the same element.

We have

dimSyml(V)=(n+l1l)=(n+l1n1)\dim\operatorname{Sym}^{l}(V)=\binom{n+l-1}{l}=\binom{n+l-1}{n-1}

where dimV=n\dim V=n. Indeed, if 𝐞1,,𝐞n{\bf e}_{1},\ldots,{\bf e}_{n} is a basis for VV then a basis for Syml(V)\operatorname{Sym}^{l}(V) is

{𝐞i1𝐞il| 1i1i2iln}\{{\bf e}_{i_{1}}\ldots{\bf e}_{i_{l}}\,|\,1\leq i_{1}\leq i_{2}\leq\ldots\leq i% _{l}\leq n\}

from which finding the dimension is a simple counting problem.

The action of GG is

Symlρ(g)(𝐯1𝐯l)=(ρ(g)𝐯1)(ρ(g)𝐯l),\operatorname{Sym}^{l}\rho(g)({\bf v}_{1}\ldots{\bf v}_{l})=(\rho(g){\bf v}_{1% })\ldots(\rho(g){\bf v}_{l}),

for all gGg\in G, and all 𝐯1𝐯lSyml(V){\bf v}_{1}\ldots{\bf v}_{l}\in\operatorname{Sym}^{l}(V).

Lemma 2.9.8.

Suppose (Symlρ,Syml(V))(\operatorname{Sym}^{l}\rho,\operatorname{Sym}^{l}(V)) is the llth symmetric product of a representation of GG. Then the derivative of this representation is given by

DSymlρ(X)(𝐯1𝐯l)=(Dρ(X)𝐯1)𝐯2𝐯l++𝐯1𝐯l1(Dρ(X)𝐯l),D\operatorname{Sym}^{l}\rho(X)({\bf v}_{1}\ldots{\bf v}_{l})=(D\rho(X){\bf v}_% {1}){\bf v}_{2}\ldots{\bf v}_{l}+\ldots+{\bf v}_{1}\ldots{\bf v}_{l-1}(D\rho(X% ){\bf v}_{l}),

for all X𝔤X\in\mathfrak{g}, and all 𝐯1𝐯lSyml(V){\bf v}_{1}\ldots{\bf v}_{l}\in\operatorname{Sym}^{l}(V).

Proof.

Exercise. ∎

Definition 2.9.9.

The llth alternating product is the space l(V)\bigwedge^{l}(V) generated by symbols 𝐯1𝐯l{\bf v}_{1}\wedge\ldots\wedge{\bf v}_{l} with linearity in each entry and having the alternating property: for any permutation σSl\sigma\in S_{l}, we have

𝐯σ(1)𝐯σ(l)=ϵ(σ)(𝐯1𝐯l).{\bf v}_{\sigma(1)}\wedge\ldots\wedge{\bf v}_{\sigma(l)}=\epsilon(\sigma)({\bf v% }_{1}\wedge\ldots\wedge{\bf v}_{l}).

In particular, switching the places of two components reverses the sign, while 𝐯1𝐯l=0{\bf v}_{1}\wedge\ldots\wedge{\bf v}_{l}=0 if two of the vectors coincide (more generally, if they are linearly dependent). Thus if l>dimVl>\dim V we have lV=0\bigwedge^{l}V=0.

We have

dimlV=(nl)\dim\textstyle\bigwedge^{l}V=\binom{n}{l}

where dimV=n\dim V=n. Indeed, if 𝐞1,,𝐞n{\bf e}_{1},\ldots,{\bf e}_{n} are a basis for VV then a basis for l(V)\bigwedge^{l}(V) is

{𝐞i1𝐞il| 1i1<i2<<iln}\{{\bf e}_{i_{1}}\wedge\ldots\wedge{\bf e}_{i_{l}}\,|\,1\leq i_{1}<i_{2}<% \ldots<i_{l}\leq n\}

from which finding the dimension is a simple counting problem. In particular, nn\bigwedge^{n}\mathbb{C}^{n} is one-dimensional generated by 𝐞1𝐞n{\bf e}_{1}\wedge\ldots\wedge{\bf e}_{n}.

The representation on l(V)\bigwedge^{l}(V) is

lρ(g)(𝐯1𝐯l)=ρ(g)𝐯1ρ(g)𝐯l,\textstyle\bigwedge^{l}\rho(g)({\bf v}_{1}\wedge\ldots\wedge{\bf v}_{l})=\rho(% g){\bf v}_{1}\wedge\ldots\wedge\rho(g){\bf v}_{l},

for all gGg\in G, and all 𝐯1𝐯ll(V){\bf v}_{1}\wedge\ldots\wedge{\bf v}_{l}\in\bigwedge^{l}(V).

Lemma 2.9.10.

Suppose (lρ,l(V))(\bigwedge^{l}\rho,\bigwedge^{l}(V)) is the llth alternating product of a representation of GG. Then the derivative of this representation is given by

Dlρ(X)(𝐯1𝐯l)=Dρ(X)𝐯1𝐯2𝐯l++𝐯1𝐯l1Dρ(X)𝐯l.D\textstyle\bigwedge^{l}\rho(X)({\bf v}_{1}\ldots{\bf v}_{l})=D\rho(X){\bf v}_% {1}\wedge{\bf v}_{2}\wedge\ldots\wedge{\bf v}_{l}+\ldots+{\bf v}_{1}\wedge% \ldots\wedge{\bf v}_{l-1}\wedge D\rho(X){\bf v}_{l}.

for all gGg\in G, and all 𝐯1𝐯ll(V){\bf v}_{1}\wedge\ldots\wedge{\bf v}_{l}\in\bigwedge^{l}(V).

Proof.

Exercise. ∎

Remark 2.9.11.

We defined tensor products (and so on) of representations of Lie groups and then differentiated them. We could also directly make these definitions with Lie algebras. For instance, if 𝔤\mathfrak{g} is a Lie algebra and (π,V)(\pi,V) is a representation of 𝔤\mathfrak{g}, we define the symmetric square representation on Sym2(V)\operatorname{Sym}^{2}(V) by

π(X)(𝐯𝐰)=(π(X)𝐯)𝐰+𝐯(π(X)𝐰).\pi(X)({\bf v}{\bf w})=(\pi(X){\bf v}){\bf w}+{\bf v}(\pi(X){\bf w}).

Functional constructions

We can construct representations as vector spaces of functions on topological spaces with actions of GG. If GG acts on a set XX, then it also acts on the vector space of functions XX\rightarrow\mathbb{C} by (gf)(x)=f(g1x)(g\cdot f)(x)=f(g^{-1}x). Usually this will be infinite dimensional, and so out of the scope of our course, but sometimes we can impose conditions allowing us to handle it. For example, GLn()\operatorname{GL}_{n}(\mathbb{C}) acts on n\mathbb{C}^{n}, and hence on the space of polynomial functions in nn variables. Imposing a further restriction — to homogeneous polynomials of some fixed degree — gives a finite-dimensional representation. The derivative must be calculated on a case-by-case basis. We will see examples of this on the problem sheet.

2.9.2. Exercises

.

Problem 23. Prove Lemmas 2.9.8 and 2.9.10.

Problem 24.

  1. (a)

    If (ρ,V)(\rho,V) is an irreducible finite-dimensional complex representation of 𝔤\mathfrak{g} and 𝔷\mathfrak{z} is the centre of 𝔤\mathfrak{g} (see problem 1.7.3), show that there is a linear map α:𝔷\alpha:\mathfrak{z}\rightarrow\mathbb{C} such that ρ(Z)𝐯=α(Z)𝐯\rho(Z){\bf v}=\alpha(Z){\bf v} for all Z𝔷Z\in\mathfrak{z}.

  2. (b)

    For 𝔤=GLn,\mathfrak{g}=\operatorname{GL}_{n,\mathbb{C}}, find 𝔷\mathfrak{z}. Find α\alpha when V=knV=\bigwedge^{k}\mathbb{C}^{n}, where n\mathbb{C}^{n} is the standard representation and 1kn1\leq k\leq n. These representations are in fact irreducible, though we haven’t proved that yet; you can just directly show that α\alpha exists.

Problem 25. Let V=2V=\mathbb{C}^{2} be the standard representation of GL2()\operatorname{GL}_{2}(\mathbb{C}).

  1. (a)

    Show that 2(V)det\bigwedge^{2}(V)\cong\det as Lie group representations.

  2. (b)

    Show that 2(V)tr\bigwedge^{2}(V)\cong\operatorname{tr} as representations of 𝔤𝔩2()\mathfrak{gl}_{2}(\mathbb{C}). (You could just ‘take the derivative’ of part (a), but please do it directly instead.)

  3. (c)

    Find an explicit homomorphism ρ:GL2()GL3()\rho:\operatorname{GL}_{2}(\mathbb{C})\rightarrow\operatorname{GL}_{3}(\mathbb% {C}) corresponding to Sym2(V)\operatorname{Sym}^{2}(V).